Wednesday

July 30, 2014

July 30, 2014

Posted by **Andy** on Wednesday, May 14, 2008 at 8:11pm.

Evaluate the indefinate integral

(x^4-6x)dx

- Mathmatics -
**drwls**, Wednesday, May 14, 2008 at 8:32pmAdd the separate integrals of the two terms.

The integral of x^4 dx is x^5/5.

The integral of -6 x dx is -6*(1/2)x^2 = -3x^2.

Add an arbitrary constant C to the sum.

(x^5)/5 - 3 x^2 + C

- Mathmatics -
**Andy**, Wednesday, May 14, 2008 at 8:34pmWait, is that the answer

- Mathmatics -
**Andy**, Wednesday, May 14, 2008 at 8:36pman would it be (x^5/5) or is the whole rest besides the C on the bottom.

- Mathmatics -
**drwls**, Wednesday, May 14, 2008 at 8:39pmThe answer is the last line I wrote

- Mathmatics -
**Andy**, Wednesday, May 14, 2008 at 8:44pmI know, but I don't see what you mean

Is 5-3x^2 all under x^5

- Mathmatics -
- Mathmatics -
**drwls**, Wednesday, May 14, 2008 at 8:46pmNo. 3x^2 and C are separate additive terms. As I said in the beginning, you add the integrals of each term.

- Mathmatics -
**Andy**, Wednesday, May 14, 2008 at 8:48pmso, the answer would be like this

(x^5/5)-3x^2+C

- Mathmatics -

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