Posted by **Kelsey** on Wednesday, May 14, 2008 at 2:00am.

I need help with this problem:

Two planes start from Los Angeles International Airport and fly in opposite directions. The second plane starts ½ hour after the first plane, but its speed is 80 kilometers per hour faster. Find the airspeed of each plane if 2 hours after the first plane departs the planes are 3200 kilometers apart.

- Math -
**bobpursley**, Wednesday, May 14, 2008 at 3:28am
distance slow plane=vt

distance fast plane=.5*(v+80)t +(v+80)t

3200=sum of the two distances, or

3200=v*2+.t(v+80)*2 + (v+80)*2

solve for v, then for the faster plane, its speed is v+80

- Math -
**bobpursley**, Wednesday, May 14, 2008 at 3:39am
40 times five is 200

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