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What would you do...

(4)^(3/square root 2) ÷ 16^(2*square root 2) ?

  • Math - ,

    Recognize that
    16^(2*square root 2)= (4^2)^(2sqrt2)
    = 4^(4sqrt2)

    So your expression can be written
    4^(3/sqrt2)/4^(4sqrt2)
    = 4^[(3/sqrt2)-(4sqrt2)]
    = 4^[(3/2)sqrt2-4sqrt2]
    = 4^[-(5/2)sqrt2]
    = 2(-5sqrt2)
    I might have made a mistake somewhere, so be sure to verify the steps.

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