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December 22, 2014

December 22, 2014

Posted by **Victoria** on Wednesday, May 14, 2008 at 1:04am.

(4)^(3/square root 2) ÷ 16^(2*square root 2) ?

- Math -
**drwls**, Wednesday, May 14, 2008 at 1:59amRecognize that

16^(2*square root 2)= (4^2)^(2sqrt2)

= 4^(4sqrt2)

So your expression can be written

4^(3/sqrt2)/4^(4sqrt2)

= 4^[(3/sqrt2)-(4sqrt2)]

= 4^[(3/2)sqrt2-4sqrt2]

= 4^[-(5/2)sqrt2]

= 2(-5sqrt2)

I might have made a mistake somewhere, so be sure to verify the steps.

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