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differentiate y = tan^2(3x) + sec^2(3x)

  • maths - ,

    Use the chain rule separately for each of the two terms. The first term can be differentiated as follows:

    Let u = tan 3x and v = u^2
    tan^2(3x) = v{u(x)}

    d/dx [tan^2(3x)] = (dv/du)*(du/dx)
    = 2u * 3 sec^2 3x
    = 6 tan(3x)*sec^2(3x)

    Use a similar procedure to differentiate sec^2(3x)

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