Saturday

December 20, 2014

December 20, 2014

Posted by **Andrew** on Monday, May 12, 2008 at 9:38pm.

of popcorn to pop is normally distributed with a mean of 140 seconds and a standard deviation of

25 seconds. What percentage of the kernels will fail to pop if the popcorn is cooked for (a) 2 minutes?

(b) Three minutes? (c) If you wanted 95 percent of the kernels to pop, what time would you

allow? (d) If you wanted 99 percent to pop?

- Statistics -
**MathGuru**, Thursday, May 15, 2008 at 8:08amYou will need to use the z-score formula and a z-table to answer these questions.

The formula:

z = (x - mean)/sd -->sd = standard deviation

For a) and b), find z using the formula. Then determine the percentage using the z-table.

For c) and d), find x using the formula (which means you will need to find z equating to 95% and 99% in the table).

I'll get you started and let you take it from there.

a) z = (120 - 140)/25

b) z = (180 - 140)/25

c) 1.28 = (x - 140)/25

d) 2.33 = (x - 140)/25

I hope this will help.

**Answer this Question**

**Related Questions**

statistics - Why might the following not be normally distributed? (a) The time ...

statistics - Why might the following not be normally distributed? (a) The time ...

statistics - It is well known that the heights of individual American men are ...

statistics - An automatic machine that fills bags of unpopped popcorn is ...

statistics - An automatic machine that fills bags of unpopped popcorn is ...

statistics - Suppose the amount of time it takes for statistics students to ...

Statistics - The weights of the fish in a certain lake are normally distributed ...

statistics - IQ is normally distributed with a mean of 100 and a standard ...

Chemistry - Popcorn kernels pop independently (i.e. unimolecularly). For one ...

statistics - The weights of a group of adult males are normally distributed with...