Posted by **Donna** on Sunday, May 11, 2008 at 11:12pm.

If 3xy^3 - 4x = 10y^2, find y ' (x)

a) (4 + 3y^2)/(9xy^2 + 20y)

b) (4 - 3y^2)/(9xy^2 - 20y)

c) (3 + 4y^2)/(20xy^2 + 9y)

d) (3 - 4y^2)/(20xy^2 - 9y)

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