For all real numbers, f(x)=(x^2+1)/2. If f(a)=25 and f(11)=b, what could be the value of b-a?
I'm confused on how you do these problems. Can someone show me how to do them? Thanks much!
Math - bobpursley, Sunday, May 11, 2008 at 6:01pm
I will start you on b
f(11)=(11^2+1)/2=61 so b is 61
25=(a^2+1)/2 solve for a....
Math - Monique, Sunday, May 11, 2008 at 6:13pm
Ok, so f(25)=(25^2+1)/2. 626/2=313. So, a=313. When substituted, 61-313 is -252.
There's a small issue though. This question is multiple, and I don't see a -252 as one of the choices:
Did I do something wrong?