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THe length of a rectangle is twice the width. The area is 200yd^2. What is the length and width. Is this right

  • algebra - ,

    L * W = 200
    L = 2W

    Substitute 2W for L in the first equation and solve for W. Once you find W, insert that into the second equation to find L.

    I hope this helps. Thanks for asking.

  • algebra - ,

    well check it
    check #1, yes, length is twice width
    check #2, yes, the area is 20*10 = 200
    however remember the units
    20 Yards by 10 yeards

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