Posted by Danny on Sunday, May 11, 2008 at 10:14am.
Please repost with completed question. Thanks for asking.
binomial
p(r) = C(n,r) p^(r) (1-p)^(n-r)
here n = 3 , p=.6 (boy), (1-p)=.4 (girl)
p(0 boys) = 1*.6^0* .4^3 = .064
p(1 boy ) = 3 *.6^(1) *.4^2 = .288
p(2 boys) = 3*.6^2*.4^1 = .432
p(3 boys) = 1*.6^3*.4^0 = .216
I guess whatever your question might be, that might help.
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