Posted by **Victoria** on Saturday, May 10, 2008 at 5:00pm.

Question – 3: Consider a particle moving according to the velocity function,

v(t) = 2a-3exp(-2t)+2/t+2,for t>0.

(a) If the net distance,d,covered by the particle in the time interval,[0,3],is 20,find the value of a. What is the terminal velocity of the particle?.

(b) Find the expression for the trajectory,y(t), such that, y(2) = 5 . Find the initial position of the particle.

(c) Find the acceleration, a(t), of the particle, for t > 0.

Find the acceleration when the velocity is 6.55 m/s.

## Answer this Question

## Related Questions

- calculus - The velocity function is v(t) = - t^2 + 4 t - 3 for a particle moving...
- math - The velocity function is v(t) = t^2 - 6 t + 8 for a particle moving along...
- Calculus III - A particle is moving in R2 according to the law x=t^2, y=t^3 (...
- Calculus-particle motion - 1. A particle is moving on the x-axis (or any number ...
- calculus - 5. A particle moves along the y – axis with velocity given by v(t)=...
- Calculus - The position of a particle moving on a horizontal line is given by s(...
- AP Calculus - The position of a particle moving on the x-axis at time t>0 ...
- Calculus - At time t >or= to 0, the position of a particle moving along the x...
- Math: Calculus - The velocity function is v(t)= t^2-5t+ 4 for a particle moving ...
- math - The velocity function (in meters per second) for a particle moving along ...

More Related Questions