Wednesday

August 20, 2014

August 20, 2014

Posted by **Wanda** on Friday, May 9, 2008 at 4:50pm.

My answer: pi/3, 2pi/3, 4pi/3, 5pi/3

2. 4cos^2 (x) - 1 = 0

My answer: pi/3, 2pi/3, 5pi/3, 4pi/3

3. 2sin (x) + csc (x) = 0

My answer: unknown lol

i got to the part: sin^2 (x) = -1/2

4. 4sin^3 (x) + 2sin^2 (x) - 2sin^2 (x) = 1

- trig -
**Damon**, Friday, May 9, 2008 at 5:19pm3. 2sin (x) + csc (x) = 0

My answer: unknown lol

i got to the part: sin^2 (x) = -1/2

=============================

I do not know what to do either. There is no real solution.

4 looks like a typo. The second two terms are identical and cancel each other.

Are you sure it is not:

4 sin^3 x + 2 sin^2 x - 2 sin x = 1 ???

if so

let y = sin x

then

4 y^3 + 2 y^2 -2 y - 1 = 0

factor that

(2y+1) works

(2y+1)(2 y^2-1) = 0

y = sin x = -1/2

y = sin x = + ( sqrt 2) /2

y = sin x = - (sqrt 2) / 2

You can do it from there

- trig -
**Wanda**, Friday, May 9, 2008 at 5:26pmThank you!

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