3. 2sin (x) + csc (x) = 0
My answer: unknown lol
i got to the part: sin^2 (x) = -1/2
I do not know what to do either. There is no real solution.
4 looks like a typo. The second two terms are identical and cancel each other.
Are you sure it is not:
4 sin^3 x + 2 sin^2 x - 2 sin x = 1 ???
let y = sin x
4 y^3 + 2 y^2 -2 y - 1 = 0
(2y+1)(2 y^2-1) = 0
y = sin x = -1/2
y = sin x = + ( sqrt 2) /2
y = sin x = - (sqrt 2) / 2
You can do it from there
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