A rectangle has a length of 19 cm, and a width of 16 cm. What is the length of its diagonal?
dia^2=19^2 + 16^2
or
do it with trig.
tan Theta= 16/19
sinTheta= 16/dia
dia= 16/sin (arctan16/19)
2x^2-x-28=0
To find the length of the diagonal of a rectangle, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.
In this case, the length and width of the rectangle form the legs of a right triangle, and the diagonal is the hypotenuse. Let's call the length of the rectangle 'L' and the width 'W'.
The Pythagorean theorem equation for this rectangle would be:
Diagonal^2 = Length^2 + Width^2
Plugging in the given values:
Diagonal^2 = 19^2 + 16^2
Diagonal^2 = 361 + 256
Diagonal^2 = 617
Diagonal ≈ sqrt(617)
Diagonal ≈ 24.8 cm
Therefore, the length of the diagonal of the rectangle is approximately 24.8 cm.