posted by sonia .
The equation of the tangent line to y=f(x) at a=2 can be written in the form y=mx+b where f(x) =4sinx/4sinx+6cosx
i already got 3/2 for m but i cant seem to find out how to get the value of b?
Does f(x) = 4 sinx/(4sinx+6cosx) ?
If so, you need parentheses in the denominator.
You say you want the tangent point to be at a=2. Do you mean x=2? Or x = 2 pi? I don't see how you can get 3/2 for the slope if the equation involves the sin and cos of 2.
If you have the correct slope m, then you can get b by requiring that the value of y = mx + b be the same at the value of f(x) at at the point of contact.