Posted by **sonia** on Friday, May 9, 2008 at 12:54am.

The equation of the tangent line to y=f(x) at a=2 can be written in the form y=mx+b where f(x) =4sinx/4sinx+6cosx

i already got 3/2 for m but i cant seem to find out how to get the value of b?

- calc -
**drwls**, Friday, May 9, 2008 at 9:04am
Does f(x) = 4 sinx/(4sinx+6cosx) ?

If so, you need parentheses in the denominator.

You say you want the tangent point to be at a=2. Do you mean x=2? Or x = 2 pi? I don't see how you can get 3/2 for the slope if the equation involves the sin and cos of 2.

If you have the correct slope m, then you can get b by requiring that the value of y = mx + b be the same at the value of f(x) at at the point of contact.

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