Posted by sara on Friday, May 9, 2008 at 12:07am.
If 4x2+3x+xy=2 and y(2)=–10 , find y'(2) by implicit differentiation.
i keep getting the wrong answer for this problem evn when plugging 2 in for y.

calc  JP, Friday, May 9, 2008 at 12:31am
d/dx(4x^2+3x+xy)=d/dx(2)
8x+3+y+xy'=0
At x=2, y=10, we get
16+310+2y'=0
Solving for y' yields y'(2)=9/2.
You are not suppose to plug in 2 for y. y(2)=10 means that the function has a value of 10 when x=2.

calc  Anonymous, Wednesday, March 16, 2011 at 4:05pm
OMG this helped soooo much!!! thank you!!!
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