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February 28, 2015

February 28, 2015

Posted by **sara** on Friday, May 9, 2008 at 12:07am.

i keep getting the wrong answer for this problem evn when plugging 2 in for y.

- calc -
**JP**, Friday, May 9, 2008 at 12:31amd/dx(4x^2+3x+xy)=d/dx(2)

8x+3+y+xy'=0

At x=2, y=-10, we get

16+3-10+2y'=0

Solving for y' yields y'(2)=-9/2.

You are not suppose to plug in 2 for y. y(2)=-10 means that the function has a value of -10 when x=2.

- calc -
**Anonymous**, Wednesday, March 16, 2011 at 4:05pmOMG this helped soooo much!!! thank you!!!

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