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calc

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If 4x2+3x+xy=2 and y(2)=–10 , find y'(2) by implicit differentiation.

i keep getting the wrong answer for this problem evn when plugging 2 in for y.

  • calc - ,

    d/dx(4x^2+3x+xy)=d/dx(2)
    8x+3+y+xy'=0
    At x=2, y=-10, we get
    16+3-10+2y'=0
    Solving for y' yields y'(2)=-9/2.

    You are not suppose to plug in 2 for y. y(2)=-10 means that the function has a value of -10 when x=2.

  • calc - ,

    OMG this helped soooo much!!! thank you!!!

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