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March 28, 2017

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can someone please show me step by step how to do this problem...
1/2log base 4 25-2(3logbase4 5-log base 4 25)

  • alg 2. - ,

    .5 log4 5^2 = log4(5)

    2(3 log4 5 - 2 log4 5 ) = 2 log4 5
    so we have
    -1 log4(5)
    = log4(.2)

    that might be the answer you are looking for but if you need a number
    4^x = .2 ?
    x ln 4 = ln .2
    x = 1.39/-1.61
    = - .863

  • alg 2. - ,

    I have to condense it... thanks for your help

  • alg 2. - ,

    1/2log base 4 25-2(3logbase4 5-log base 4 25)
    = 1/2 log4 25 - 2(3log4 5 - log4 25)
    = log45 - 2(log4125 - log425)
    = log45 - 2(log4(125/25)
    = log45 - 2log45
    = -log45

  • alg 2. - ,

    my teacher has a different answer... she has log base 4(1/25).

  • alg 2. - ,

    Well, I think log4 (1/5)
    I got -1 log4 5
    she got -2 log4 5
    one of us subtracted wrong or something
    However Reiny and I agree exactly, so the odds are in our favor :

  • alg 2. - ,

    my teacher got log base 4 (1/125) and it's a quiz review sheet, and all the math teachers look over it... sooo... I get how to simplify the 1/2 part but how do i condense the parenthesies

  • alg 2. - ,

    Well, Miley, if you typed your question correctly, then your teacher is wrong.

    Even though both Damon and I did it slightly differently, we came up with the same answer.

    I evaluated your original expression the way it stands on my calculator, and got the same result as our answer at the end.

  • alg 2. - ,

    By the way, your teacher and I both said
    -n log4 x = log4 x^-n = log4 (1/x^n)
    which is how we converted the negative log to positive

  • alg 2. - ,

    can you please show me how to condense -2(3logbase 4 5-log base 4 5), thanks:)

  • alg 2. - ,

    OK, Miley, in your first post you had

    ...-2(3logbase4 5-log base 4 25)

    and now you typed
    ...-2(3logbase4 5-log base 4 5)


    GheeeeZZ!!!!

  • alg 2. - ,

    Sorry it's not like i did that on purpose! Take a CHILL PILL!

  • alg 2. - ,

    I do not know what to say. Reiny and I did the parentheses quite different ways and both got the same answer.

  • alg 2. - ,

    Can you please break it down step by step and show me how you did it! thanks:)

  • alg 2. - ,

    You have two ways to condense the inside the parentheses up there

    I did it by saying log 25 = 2 log 5

    Reiny did it by saying
    log 125 - log 25 = log (125/25) = log 5

  • alg 2. - ,

    what happen to the base 4?

  • alg 2. - ,

    What I wrote a few minutes ago is true for any old base so I left the 4 out

  • alg 2. - ,

    ohh okay thanks

  • alg 2. - ,

    -2(3logbase 4 5-log base 4 5)
    Hey, that is not what you wrote in the original question
    that is just -2 (2 log4 5)
    which is
    -4 log4 of 5

    NOW
    log4 5 - 4 log4 5
    = -3 log4 5
    = log4 (1/5^3)
    = log4 (1/125)

  • alg 2. - ,

    oh my bad, sorry. wait how did you get rid of the negative two on the outside?

  • alg 2. - ,

    -2(2 log) = -4 log

  • alg 2. - ,

    huh??

  • alg 2. - ,

    Uh...I'm posting this one on gothomework.tk

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