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November 20, 2014

November 20, 2014

Posted by **jesus** on Wednesday, May 7, 2008 at 11:46pm.

- algebra -
**Ryan**, Thursday, May 8, 2008 at 12:46am16bc+12b(squared)+20c(squared)+15bc

12b(squared)+ 20c (squared)+ 31bc

- algebra -
**PsyDAG**, Thursday, May 8, 2008 at 12:26pm(4b+5c)(4c+3b) = (4b+5c)(3b+4c)

4b + 5c

3b + 4c

Multiplying

16bc+20C^2

12b^2+15bc

= 12b^2+31bc+20c^2

I hope this makes the process clearer. Thanks for asking.

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