Bulb P is rated 60 W, 110 V, and bulb Q is rated 100 W, and 110 V. Which of the bulbs has the higher resistance?

they have the same
cannot be determined
bulb P
bulb Q

I had they have the same.

Power = E2/R

Calculate R for each bulb.

To determine which bulb has the higher resistance, we can use Ohm's Law, which states that resistance (R) equals voltage (V) divided by current (I). In this case, we only have the values for power (P) and voltage (V) for each bulb.

First, let's calculate the current (I) for each bulb using the formula P = IV, where P is the power and V is the voltage:

For bulb P:
P = 60 W
V = 110 V
60 = 110 * I
I = 60/110 ≈ 0.545 A

For bulb Q:
P = 100 W
V = 110 V
100 = 110 * I
I = 100/110 ≈ 0.909 A

Now we can calculate the resistance (R) for each bulb using Ohm's Law (R = V/I):

For bulb P:
V = 110 V
I = 0.545 A
R = 110/0.545 ≈ 201.8 Ω

For bulb Q:
V = 110 V
I = 0.909 A
R = 110/0.909 ≈ 120.9 Ω

Comparing the calculated values, we can see that bulb P has a resistance of approximately 201.8 Ω, while bulb Q has a resistance of approximately 120.9 Ω. Therefore, bulb P has the higher resistance.