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Posted by on Wednesday, May 7, 2008 at 9:04pm.

Calculate the volume of a 9.00 M HNO3 stock solution that must be used to prepare 450 mL 0f a 1.80 M HNO3 solution.

  • chemistry - , Wednesday, May 7, 2008 at 9:11pm

    M x V = M x V (good for dilution problems only).

  • chemistry - , Wednesday, May 7, 2008 at 10:49pm

    so which ones do i times together?

  • chemistry - , Wednesday, May 7, 2008 at 10:56pm

    molarity of concd HNO3 x mL concd HNO3 = molarity of the diluted solution x mL of the diluted solution.

  • chemistry - , Wednesday, May 7, 2008 at 11:06pm

    so is just 9.00x 450x1.80??

  • chemistry - , Wednesday, May 7, 2008 at 10:58pm

    9.00 x 450x 1.80?

  • chemistry - , Wednesday, May 7, 2008 at 11:22pm

    Where is the equal sign?
    I would do it this way.
    9.00 M x ??mL = 1.80 M x 450 mL
    and solve for ?? mL.
    Isn't that what my instructions said?
    M concd soln x mL concn soln = M dilute soln x mL dilute soln.

  • chemistry - , Wednesday, May 7, 2008 at 11:26pm

    9.00x?mL=810

    how do i find the missing number

  • chemistry - , Wednesday, May 7, 2008 at 11:31pm

    You solve for ? mL. This is an ordinary equation.
    9.00 x unknown mL = 810.
    Solve for unknown mL.

  • chemistry - , Wednesday, May 7, 2008 at 11:35pm

    ok so to find it...do i subtract them..or divide?

  • chemistry - , Wednesday, May 7, 2008 at 11:49pm

    You divide. It has taken me most of the night but I think I know what your problem is. It isn't chemistry. It is arithmetic and algebra. You apparently don't know how to solve an equation.
    When we had pH + pOH = 14 and we substituted to give
    9.21 + pOH = 14, I had to tell you that pOH = 14 - 9.21 and you obtained the correct answer of 4.79.
    For this problem, we have 9.00X = 810.
    You solve for the unknown by
    X = 810/9.00 = 90; therefore, you take 90 mL of the concd HNO3 (which is 9.00 M), make the total volume to 450 mL, and you end up with 450 mL of 1.80 M HNO3. I recommend that you find a tutor who can help you with algebraic manipulations.
    You will do your self a huge favor if you contact someone at your school (a counselor, department head, etc) and ask about a tutor.

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