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August 30, 2014

August 30, 2014

Posted by **katie** on Wednesday, May 7, 2008 at 7:54pm.

- chemistry -
**DrBob222**, Wednesday, May 7, 2008 at 8:09pm(P1V1)/T1 = (P2V2)/T2

Use 170 atm for P1 and the answer will be in atm. Don't forget to use Kelvin for T1 and T2.

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**katie**, Wednesday, May 7, 2008 at 9:30pmi dont understand this at alll

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- chemistry -
**DrBob222**, Wednesday, May 7, 2008 at 10:33pmYou plug in 170 atm for P1, there is no V1 or V2 in the problem, and T1 = 25 degrees C which si 273 + 25 = ??Kelvin. Continuing, P2 is what you want to know, V2 is not in the problem, and T2 is 60 degrees which must be convert to Kelvin. Then solve for P2.

- chemistry -
**katie**, Wednesday, May 7, 2008 at 10:40pmokay so does it kinda look like this

(170)/298/333...i kinda understand not really

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- chemistry -
**DrBob222**, Wednesday, May 7, 2008 at 10:44pmWe have P1/T1 = P2/V2

You have P1 in the right place with the right number. Yuo have 298 ok. I don't see an equal sign. I don't see P2 (which you're solving for) and the 333 (the right number Kelvin) is not in the right place. Follow the guideline above. The equation is

P1/T1 = P2/T2.

Solve for P2 but substitute the numbers first and solve it step by step.

- chemistry -
**katie**, Wednesday, May 7, 2008 at 10:47pmok so 170/298=P2/333

which is .570...how do i find P2

- chemistry -
**katie**, Thursday, May 8, 2008 at 12:33amok so 170/298=P2/333

which is .570...how do i find P2

- chemistry -
**DrBob222**, Thursday, May 8, 2008 at 12:40am

170/298 = P2/333

0.570 = P2/333

P2 = 0.570 x 333 = ?? atm.

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- chemistry -

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