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February 1, 2015

February 1, 2015

Posted by **Christine** on Wednesday, May 7, 2008 at 11:09am.

y' + (y)tanh(x) - 2e^x = 0

- calculus -
**Count Iblis**, Wednesday, May 7, 2008 at 2:00pmFirst solve the homogeneous equation:

y' + (y)tanh(x)= 0

Replace the integration constant by an unknown function and substitute that back in the Diff. equation:

y' + (y)tanh(x) - 2e^x = 0

then solve for that unknown function.

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