Posted by Christine on .
solve the following differential equation:
y' + (y)tanh(x)  2e^x = 0

calculus 
Count Iblis,
First solve the homogeneous equation:
y' + (y)tanh(x)= 0
Replace the integration constant by an unknown function and substitute that back in the Diff. equation:
y' + (y)tanh(x)  2e^x = 0
then solve for that unknown function.