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March 29, 2015

March 29, 2015

Posted by **Jennifer** on Tuesday, May 6, 2008 at 6:46pm.

Find the least integral upper bound of the zeros of the function f(x)=x^3-x^2+1

So by the rational root theorem, 1 and -1 might be roots.

by using synthetic division, i get the following values:

for f(-1)=-1

f(0)=1

f(1)=1

f(2)=5

and there is changes in the signs of the remainder/quotient for -1 and 0, but no changes for 1 and 2.

So would 1 be the upper bound, or 2?

Thanks for the help.

- math-intergral upper bound -
**Jennifer**, Tuesday, May 6, 2008 at 6:49pmafter-thoughts:

the only real zero is negative, so I guess would 0 be the upper bound? maybe? lol

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