math-intergral upper bound
posted by Jennifer on .
This one has me stumped.
Find the least integral upper bound of the zeros of the function f(x)=x^3-x^2+1
So by the rational root theorem, 1 and -1 might be roots.
by using synthetic division, i get the following values:
and there is changes in the signs of the remainder/quotient for -1 and 0, but no changes for 1 and 2.
So would 1 be the upper bound, or 2?
Thanks for the help.
the only real zero is negative, so I guess would 0 be the upper bound? maybe? lol