can someone help me with the steps for finding how f(0);f(7a) are the inputs for the nonlinear function?
f(x) = 3x² – 2x + 8
To find the values of f(0) and f(7a) for the nonlinear function f(x) = 3x² – 2x + 8, follow these steps:
Step 1: For f(0), substitute 0 into the function for x.
f(0) = 3(0)² – 2(0) + 8
Step 2: Simplify the expression.
f(0) = 0 – 0 + 8
f(0) = 8
So, f(0) = 8.
Step 3: For f(7a), substitute 7a into the function for x.
f(7a) = 3(7a)² – 2(7a) + 8
Step 4: Simplify the expression.
f(7a) = 3(49a²) – 14a + 8
f(7a) = 147a² – 14a + 8
So, f(7a) = 147a² – 14a + 8.
Therefore, the values of f(0) and f(7a) for the given nonlinear function are 8 and 147a² – 14a + 8, respectively.