Saturday

January 31, 2015

January 31, 2015

Posted by **Alex** on Saturday, May 3, 2008 at 8:57pm.

I found the velocity and acceleration functions.

s'(t) = 3t^2 - 18t + 24

s''(t) = 6t-18

b) When is the particle moving up? down?

c) Find the distance the particle travels between t=0 and t=6.

- Calculus -
**bobpursley**, Saturday, May 3, 2008 at 10:04pmRight on the first.

Now when it is going up> When is s'positive? When is it negative? The sign of s'is direction. Hint: factor the quadratic and test domains to see when it is +-

The distance it travels? Integrate velocity over time. The area under a velocity time graph is distance.

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