Posted by **Alex** on Saturday, May 3, 2008 at 8:57pm.

A particle moves on a vertical line. Its position, s, in metres at t seconds is given by s(t) = t^3 - 9t^2 + 24t, t>0/

I found the velocity and acceleration functions.

s'(t) = 3t^2 - 18t + 24

s''(t) = 6t-18

b) When is the particle moving up? down?

c) Find the distance the particle travels between t=0 and t=6.

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