Calculate the molarity of a solution in which 0.75 moles of a solute are dissolved in 125g of solution (density of solution = 1.05g/mL).
I did this much:
1.05 * 1L/1000mL = 0.001 L
I don't really know what to do.
What you did isn't much help. I don't understand it.
molarity = mols/L of solution.
you know mols. Use the density to convert 125 g solution to volume (liters) of solution.
v = m/d
v = 125g/1.05 g/mL
v = 119.mL
Then I converted mL to L
119 mL x 0.001 L/1mL = 0.119 L
Then,
M = mol/L
M = 0.75 mol/0.119 L
Final answer: 6.3 mol/L
That's my answer, too.
To calculate the molarity (M) of a solution, you need to know the number of moles of solute and the volume of the solution in liters. We can break down the steps to solve this problem:
1. Calculate the volume of the solution:
Given the density of the solution is 1.05 g/mL, and you have 125 g of the solution, you can use the following formula:
Volume (in mL) = mass (in g) / density (in g/mL)
Therefore,
Volume (in mL) = 125 g / 1.05 g/mL = 119.05 mL
But now, we need to convert this volume from milliliters to liters:
Volume (in L) = 119.05 mL * (1 L / 1000 mL) = 0.11905 L
2. Calculate the molarity of the solution:
The molarity (M) is defined as moles of solute divided by the volume of the solution (in liters). You are given that 0.75 moles of solute are dissolved.
Molarity (M) = moles of solute / volume of solution (in L)
Molarity (M) = 0.75 moles / 0.11905 L ≈ 6.3 M
Therefore, the molarity of the solution is approximately 6.3 M.