Posted by Nik on Friday, May 2, 2008 at 4:05am.
The velocity will be increased as the inverse ratio of areas:
New velocity/oldvelocity=(7.5/.8)^2
The old velocity can be solved by
450L/min*1dm^3/L * 1min/60sec is flow in dm^3/sec, so divide that by area and you get linear flow.
acceleration=changevelocity/time so on a per second basis,
acceleartion=newvelocity-oldvelocity
=oldvelocity((7.5/.8)^2-1)
and then, Force=mass/second*acceleration
= density*450L/60sec*acceleratin
check my thinking.
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