Posted by **Nik** on Friday, May 2, 2008 at 4:05am.

A fire hose exerts a force on the person holding it. This is because the water accelerates as it goes from the hose through the nozzle. How much force is required to hold a 7.5 cm diameter hose delivering 450 L/min through a 0.80cm diameter nozzle?

- physics - fluids -
**bobpursley**, Friday, May 2, 2008 at 6:28am
The velocity will be increased as the inverse ratio of areas:

New velocity/oldvelocity=(7.5/.8)^2

The old velocity can be solved by

450L/min*1dm^3/L * 1min/60sec is flow in dm^3/sec, so divide that by area and you get linear flow.

acceleration=changevelocity/time so on a per second basis,

acceleartion=newvelocity-oldvelocity

=oldvelocity((7.5/.8)^2-1)

and then, Force=mass/second*acceleration

= density*450L/60sec*acceleratin

check my thinking.

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