Posted by **william** on Friday, May 2, 2008 at 12:10am.

solve for x

6tanx - 4sinx = 1

i tried it but got a quartic formula :S

16sin^4x + 8sin^3x + 37sin^2x - 36 = 0

- trig -
**Reiny**, Friday, May 2, 2008 at 8:30am
This is a "nasty" problem and it does not simplify easily.

I don't know how you got your quartic equation.

I rewrote it as 6tanx = 1 + 4sinx

then graphed f(x) = 6tanx and

g(x) = 1+ 4sinx

There are two intersection points, one in quadrant I and another in quadrant III.

After a few iterations, I got x= 23.27ยบ to come pretty close.

This is way beyond any highschool level I know, where did you get that question ?

- trig -
**william**, Friday, May 2, 2008 at 10:51pm
I got the quartic by moving the sin to the right, squaring both sides, then multiplying everything by sin^2 and then changing the cos to sin.

My friend gave me this question, and he got it from his virtual school for gr 12 advanced functions lol.

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