posted by william .
solve for x
6tanx - 4sinx = 1
i tried it but got a quartic formula :S
16sin^4x + 8sin^3x + 37sin^2x - 36 = 0
This is a "nasty" problem and it does not simplify easily.
I don't know how you got your quartic equation.
I rewrote it as 6tanx = 1 + 4sinx
then graphed f(x) = 6tanx and
g(x) = 1+ 4sinx
There are two intersection points, one in quadrant I and another in quadrant III.
After a few iterations, I got x= 23.27º to come pretty close.
This is way beyond any highschool level I know, where did you get that question ?
I got the quartic by moving the sin to the right, squaring both sides, then multiplying everything by sin^2 and then changing the cos to sin.
My friend gave me this question, and he got it from his virtual school for gr 12 advanced functions lol.