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July 25, 2014

July 25, 2014

Posted by **Daniela Davila** on Thursday, May 1, 2008 at 11:31pm.

- Business Calculus -
**drwls**, Friday, May 2, 2008 at 7:10amLet r be the radius of the inscribed cylinder. The top edge of the cylinder (where the height is h) must touch the cone, where h and r are related by the straight-line equation

h = 8 - r.

The volume of the cone is

V (r) = pi*r^2 h = pi*r^2*(8-r)

= pi*[8 r^2 - r^3]

When the cylinder's volume is a maximum, dV/dr = 0, so

16r = 3r^2

r = 16/3, which is 2/3 the height of the come.

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