f(x)=(9x^2–8)^6(4x^2–5)^11

What's f'(x)=

i found (9x^2-8)^6 *11(4x^2-3)^10*8x+((4x^2-3)^11)6(9x^2-8)^5*(18x)

but my electronic homework says it wrong what did i do wrong?

never mind i accidentally typed in 3 instead of 5