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April 17, 2014

April 17, 2014

Posted by **Stephanie** on Wednesday, April 30, 2008 at 8:47pm.

(x^2/16) + (y^2/4) = 1

I need to find out the center, the vertices, co- vertices and the Foci.

I have trouble knowing how to find them, so if you can please explain them.

Thank you.

- Algebra 2 Honors- Ellipses -
**Reiny**, Wednesday, April 30, 2008 at 9:01pmin general

x^2/a^2 + y^2/b^2 = 1 is an ellipse with centre (0,0)

vertices (a,0) and (-a,0)

"co-vertices" (0,b), (0,-b)

foci : (c,0) and (-c,0) where c^2 = a^2 - b^2

your text should have that information for you.

Use the above to answer this question, and the same kind of question in your next post.

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