Algebra 2 Honors- Ellipses
posted by Stephanie on .
for my homework problem i have the equation:
(x^2/16) + (y^2/4) = 1
I need to find out the center, the vertices, co- vertices and the Foci.
I have trouble knowing how to find them, so if you can please explain them.
x^2/a^2 + y^2/b^2 = 1 is an ellipse with centre (0,0)
vertices (a,0) and (-a,0)
"co-vertices" (0,b), (0,-b)
foci : (c,0) and (-c,0) where c^2 = a^2 - b^2
your text should have that information for you.
Use the above to answer this question, and the same kind of question in your next post.