Saturday

December 20, 2014

December 20, 2014

Posted by **Tim** on Wednesday, April 30, 2008 at 3:53pm.

Vertex at origin, focus is at (0,3)

Equation of parabola

vertex (0,0) focus (0,3)

focus (h,k+p)

(0,0+3)

y=0-3

directrix y=-3

a=(1/4)(p)

a=(1/4(-3))=(-1/12)

a=(-1/12) h=0 k=0

y=(-1/12)(x-0)^2+0

my answer is: y=(-1/12)(x^2)+0

**Answer this Question**

**Related Questions**

Algebra - Can someone tell me if I am right? I need to find the equation of a ...

Algebra II - In this set of eight problems, we have to match each equation with ...

Math - y^2=8(x-3) how would you get the coordinates. vertex = 3,0 then what? let...

Algebra2.... - 1.) Y=-lx+1l+3 Are these correct? y-intercept=(0,2) x-intercept=(...

Algebra II-Please check fpr explanation - I have a question concerning this ...

math help,algebra - Okay this is what i have to do but i think i am doing ...

algebra - Suppose a parabola has a vertex (-4,7) and also passes through the ...

Algebra - I'm trying this again, I'd like the quadratic form, so i can then work...

Calculus - Great! I understand now that C0=f(a) c1=f'(a) c2=f"(a)/2 Now, If I am...

algebra - 1)Write an equation for the parabola with focus (1,3)and vertex(0,3) ...