Posted by **Tim** on Wednesday, April 30, 2008 at 3:53pm.

I need to find the equation of a parabola. I am not sure if this is the correct way or if I have the correct answer.

Vertex at origin, focus is at (0,3)

Equation of parabola

vertex (0,0) focus (0,3)

focus (h,k+p)

(0,0+3)

y=0-3

directrix y=-3

a=(1/4)(p)

a=(1/4(-3))=(-1/12)

a=(-1/12) h=0 k=0

y=(-1/12)(x-0)^2+0

my answer is: y=(-1/12)(x^2)+0

- algebra problem -
**Henry**, Saturday, December 5, 2015 at 9:08pm
V(0,0), F(0,3).

1/4a = 3, 4a = 1/3, a = 1/12.

Y = a(x-0)^2 + 0.

Y = (1/12)x^2.

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