A 200g Nerf dart is shot from a dart gun with a kenetic energy of 3.60J. What was the initial speed of the dart?
>>> change g into kg
Formula(i think) is: Ek=1/2 mv2
Helppp?
To find the initial speed of the dart, we can use the formula for kinetic energy:
Ek = (1/2) mv^2
where Ek is the kinetic energy, m is the mass of the dart, and v is the initial speed of the dart.
First, let's convert the mass of the dart from grams to kilograms:
Given mass = 200 grams
Converting to kilograms: 200 grams / 1000 = 0.2 kg (since there are 1000 grams in a kilogram)
Now, we can rearrange the formula to solve for v:
v^2 = (2Ek) / m
Plugging in the given values:
Kinetic energy (Ek) = 3.60 J
Mass (m) = 0.2 kg
v^2 = (2 * 3.6) / 0.2
v^2 = 36 / 0.2
v^2 = 180
Now, take the square root of both sides to find v:
v = √180
v ≈ 13.42 m/s
Therefore, the initial speed of the dart is approximately 13.42 m/s.