I want to know if this is correct.
the question is:
Marissa, Cassidy, and Shante went to a school party. Marissa brought 2 bags of Skittles, and Cassidy brought 3 bags of Skittles. Shante forgot to bring candy to the party. Each bag contained the same amount of candy. If the three students share their candy equally, and Shante paid Marissa and Cassidy a combined total of $2.50 for the candy that they shared, how much money should Marissa and Cassidy get?
The Work:
M=2 C=3 5 bags total
$.50 x 5 = 5 bags
$.50 = 1 bag
$.50 x 2 = M ($1.00)
$.50 x 3 = C ($1.50)
Marissa gets $1.00
Cassidy gets $1.50.
Looks good! Thanks for asking.
To check if this solution is correct, let's break down the problem step by step:
1. First, we need to find the total number of bags of Skittles brought to the party. Marissa brought 2 bags, and Cassidy brought 3 bags, so the total number of bags is 2 + 3 = 5 bags.
2. Next, we need to determine the value of each bag. Since Shante paid a total of $2.50 for the candy they shared, and there were 5 bags in total, we can divide $2.50 by 5 to find the value of each bag.
$2.50 ÷ 5 = $0.50
So each bag of Skittles is worth $0.50.
3. Now we can calculate how much money Marissa and Cassidy should receive.
Marissa brought 2 bags, and each bag is worth $0.50, so Marissa should receive $0.50 × 2 = $1.00.
Cassidy brought 3 bags, and each bag is worth $0.50, so Cassidy should receive $0.50 × 3 = $1.50.
Based on the calculations, Marissa should get $1.00 and Cassidy should get $1.50, which matches the solution provided. Therefore, the answer is correct.