Thursday
April 24, 2014

Homework Help: Chemistry

Posted by Sara on Monday, April 28, 2008 at 8:11pm.

Please check to see if i did it right..

if the reduction potential for
Cu^2+ + 2e---> Cu is 0.00V. Then the remaining reduction potentials for the voltages between Cu[cathode]/Zn[anode] is like???


Ecell=1.043v
My answers:Zn-->Zn2+ 2e- voltage = -1.043V

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