Thursday

October 23, 2014

October 23, 2014

Posted by **brit** on Monday, April 28, 2008 at 6:43pm.

please help

- algebra2 -
**PsyDAG**, Tuesday, April 29, 2008 at 11:14amMultiply both sides by b. (I am assuming that (b+1) and (b-1) are not denominators.)

3b-2+b = 4b-b(b+2/b-1)

3b-2+b = 4b-b^2-2+b

(b^2 = b squared.)

Combine like terms.

2b-2 = 5b-b^2-2

Add 2 to both sides.

2b = 5b-b^2

Bring all terms to the left side of the equation.

b^2-3b = 0

Factor.

b(b-3) = 0

Therefore b = 3 or 0.

I hope this helps. Thanks for asking.

**Answer this Question**

**Related Questions**

algebra2 PLEASE - what are three important thing for an evaluating and ...

Algebra2 - Please me with this thanks What is the solution of the system of ...

Algebra2 - Simplify, help please sqrt-3 + sqrt27

algebra2 help - Please explain to me how to work both these problems. Thank you...

algebra2 - solving compound inequality can someone please help I don't ...

algebra2 - What is the value of the discriminant for the quadratic equation 2a2...

algebra2 - i dont think there is a solution for this one. 3-y=1 _____ 4-y y-4 ...

algebra2 please check my answer thanks - find the asymptotes for the following ...

Algebra2 - Can someone EXPLAIN to me how to solve for x. Please don't just give ...

Algebra2........... - Using the integers 2,3,4,5, How many 3-digit odd numbers ...