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September 1, 2014

September 1, 2014

Posted by **brit** on Monday, April 28, 2008 at 6:43pm.

please help

- algebra2 -
**PsyDAG**, Tuesday, April 29, 2008 at 11:14amMultiply both sides by b. (I am assuming that (b+1) and (b-1) are not denominators.)

3b-2+b = 4b-b(b+2/b-1)

3b-2+b = 4b-b^2-2+b

(b^2 = b squared.)

Combine like terms.

2b-2 = 5b-b^2-2

Add 2 to both sides.

2b = 5b-b^2

Bring all terms to the left side of the equation.

b^2-3b = 0

Factor.

b(b-3) = 0

Therefore b = 3 or 0.

I hope this helps. Thanks for asking.

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