algebraII
posted by brit on .
3b2/b+1=4b+2/b1
please help me I'm stuck

retype with brackets to establish the correct order of operation.
did you mean
(3b2)/b+1 = (4b+2)/(b1) or
3b  2/(b+1) = 4b + 2/b1 or ... 
3b2 b+2
____=4_____
b+1 b1 
3b2/(b+1)=4(b+2)/b1

still not totally clear, I will assume you mean
(3b2)/(b+1)=4(b+2)/(b1)
so the LCD is (b1)(b1), let's multiply each term by that
(3b2)(b1) = 4(b1)(b+1)  (b+2)(b+1)
for which I go
b = 4