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An apartment has a living room whose dimensions are 2.5 m 4.8 m 5.9 m. Assume that the air in the room is composed of 79% nitrogen (N2) and 21% oxygen (O2). At a temperature of 27°C and a pressure of 1.01 105 Pa, what is the mass (in grams) of the air?

  • Physics - ,

    You don't say but I think you must be quoting percent volume.
    Find volume of room, I suggest, in cc and change to liters.

    Change liters at conditions listed to standard conditions. Standard conditions are 101 325 Pa for pressure and 273 K for temperature. Use P1V1/T1 = P2V2/T2

    corrected volume x 0.79 = volume N2 @ STP.
    corrected volume x 0.21 = volume O2@ STP.

    1 mol of a gas occupies 22.4 L @ STP; therefore,
    volume N2/22.4 = mols N2
    mols N2 x molar mass N2 = grams N2.

    volume O2/22.4 = mols O2
    mols O2 x molar mass O2 = grams O2.
    grams N2 + grams O2 = mass of air in the room. Post your work if you need more help.

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