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March 25, 2017

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The capacity of a large irregularly shaped vessel cannot be computed from geometric data. As a result, it is decided that the volume be established from analytical data. The vessel is filled to its capacity mark with calcium-free water. A known small amount of a concentrated calcium solution is added, and a homogeneous solution is obtained by stirring. The volume of the solution added is insignificant with respect to volume of the vessel.
In the experiment, 350 mL of a solution 0.735 M in Ca are added to the vessel. A 50.00 mL portion of the liquid in the vessel is removed after stirring and titrated with 0.001000 M EDTA. What is the capacity of the vessel in gallons if 32.21 mL of EDTA were required to reach the endpoint? One gallon is 3.78 liters.

  • Chemistry - ,

    mols added to vessel = M x L = 0.735 x 0.350 = 0.25725
    mols titrated in 50.00 mL = M x L = 0.001 x 0.03221 = 3.221 x 10^-5 which is
    3.221 x 10^-5 mols/0.05 L = 6.442 x 10^-4 mols/L.
    L in vessel = 0.25725 mols x L/6.442 x 10^-4 = ?? Liters in vessel.
    Convert to gallons. Check my thinking. Check my work.

    volume of vessel =

  • Chemistry - ,

    6.442 L

  • Chemistry - ,

    6.442 L in mL

  • Chemistry - ,

    0.00057 mL

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