Posted by jerson on .
Use Charles Law to solve for the missing value of each of the following a) 80.0 mL, T1= 27 degrees C, T2=77 degrees C. V2 =?
b)V1= 125 L, V2=85.0L T2=127degrees C T1=?
c) T1=33degrees C V2=54.0mL, T2=160.0 degrees C V1=?
can somebody help me with atleast a and do step by step so i can understand how to do b and c

chem again 
DrBob222,
Charles' Law is
V1/T1 = V2/T2
T must be in Kelvin. 
chem again 
jerson,
80.0 = 27
77= ???
right 
chem again 
DrBob222,
Do you know what Kelvin is? Why do you persist in using degrees C when it must be changed to Kelvin. The formulas don't work with C. They work only with Kelvin.

chem again 
jerson,
i don't know how to.. that's why i asked could if u could just help me step with step with how to do A. that way if i could see what i'm missing i could do the others and know how to do other questions.

chem again 
DrBob222,
Use Charles Law to solve for the missing value of each of the following a) 80.0 mL, T1= 27 degrees C, T2=77 degrees C. V2 =?
b)V1= 125 L, V2=85.0L T2=127degrees C T1=?
c) T1=33degrees C V2=54.0mL, T2=160.0 degrees C V1=?
80 mL....27 C. Kelvin = 27 + 273= 300 K.
V2.......77 C. Kelvin = 77 + 273= 350 K.
80/300 = V2/350
Cross multiply.
80*350 = 300*V2
Solve for ??
V2 = 80*350/300 = 93.3 mL
Check my arithmetic.
Check my work. 
chem again 
jerson,
i attempted to do b and c can you tell me if i did it right?
125...... T1
85.0 ....127 Kelvin 127+ 273= 358
125= 85
T1=358
125*358/85= 526.5
for C i did
V1... 33 C Kelvin 33+273=240
54.0ml....160 C Kelvin 160+273=433
V1=54
240=433
54*240/433=29.9
T1 
chem again 
DrBob222,
c is ok.
b would be ok but you made an error in adding 127 + 273. My calculator gives me 400 and not 358. I THINK you added in 85 which is V2 and not 127 for T2.