Posted by **jerson** on Sunday, April 27, 2008 at 6:13pm.

Use Charles Law to solve for the missing value of each of the following a) 80.0 mL, T1= 27 degrees C, T2=77 degrees C. V2 =?

b)V1= 125 L, V2=85.0L T2=127degrees C T1=?

c) T1=-33degrees C V2=54.0mL, T2=160.0 degrees C V1=?

can somebody help me with atleast a and do step by step so i can understand how to do b and c

- chem again -
**DrBob222**, Sunday, April 27, 2008 at 6:14pm
Charles' Law is

V1/T1 = V2/T2

T must be in Kelvin.

- chem again -
**jerson**, Sunday, April 27, 2008 at 6:16pm
80.0 = 27

77= ???

right

- chem again -
**DrBob222**, Sunday, April 27, 2008 at 6:18pm
Do you know what Kelvin is? Why do you persist in using degrees C when it must be changed to Kelvin. The formulas don't work with C. They work only with Kelvin.

- chem again -
**DrBob222**, Sunday, April 27, 2008 at 6:28pm
Use Charles Law to solve for the missing value of each of the following a) 80.0 mL, T1= 27 degrees C, T2=77 degrees C. V2 =?

b)V1= 125 L, V2=85.0L T2=127degrees C T1=?

c) T1=-33degrees C V2=54.0mL, T2=160.0 degrees C V1=?

**
**

80 mL....27 C. Kelvin = 27 + 273= 300 K.

V2.......77 C. Kelvin = 77 + 273= 350 K.

80/300 = V2/350

Cross multiply.

80*350 = 300*V2

Solve for ??

V2 = 80*350/300 = 93.3 mL

Check my arithmetic.

Check my work.

- chem again -
**jerson**, Sunday, April 27, 2008 at 6:59pm
i attempted to do b and c can you tell me if i did it right?

125...... T1

85.0 ....127 Kelvin 127+ 273= 358

125= 85

T1=358

125*358/85= 526.5

for C i did

V1... -33 C Kelvin -33+273=240

54.0ml....160 C Kelvin 160+273=433

V1=54

240=433

54*240/433=29.9

T1

- chem again -
**DrBob222**, Sunday, April 27, 2008 at 7:26pm
c is ok.

b would be ok but you made an error in adding 127 + 273. My calculator gives me 400 and not 358. I THINK you added in 85 which is V2 and not 127 for T2.

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