Thursday

August 28, 2014

August 28, 2014

Posted by **jerson** on Sunday, April 27, 2008 at 6:13pm.

b)V1= 125 L, V2=85.0L T2=127degrees C T1=?

c) T1=-33degrees C V2=54.0mL, T2=160.0 degrees C V1=?

can somebody help me with atleast a and do step by step so i can understand how to do b and c

- chem again -
**DrBob222**, Sunday, April 27, 2008 at 6:14pmCharles' Law is

V1/T1 = V2/T2

T must be in Kelvin.

- chem again -
**jerson**, Sunday, April 27, 2008 at 6:16pm80.0 = 27

77= ???

right

- chem again -
**DrBob222**, Sunday, April 27, 2008 at 6:18pmDo you know what Kelvin is? Why do you persist in using degrees C when it must be changed to Kelvin. The formulas don't work with C. They work only with Kelvin.

- chem again -
**jerson**, Sunday, April 27, 2008 at 6:20pmi don't know how to.. thats why i asked could if u could just help me step with step with how to do A. that way if i could see what i'm missing i could do the others and know how to do other questions.

- chem again -
- chem again -
**DrBob222**, Sunday, April 27, 2008 at 6:28pmUse Charles Law to solve for the missing value of each of the following a) 80.0 mL, T1= 27 degrees C, T2=77 degrees C. V2 =?

b)V1= 125 L, V2=85.0L T2=127degrees C T1=?

c) T1=-33degrees C V2=54.0mL, T2=160.0 degrees C V1=?

80 mL....27 C. Kelvin = 27 + 273= 300 K.

V2.......77 C. Kelvin = 77 + 273= 350 K.

80/300 = V2/350

Cross multiply.

80*350 = 300*V2

Solve for ??

V2 = 80*350/300 = 93.3 mL

Check my arithmetic.

Check my work.

- chem again -
**jerson**, Sunday, April 27, 2008 at 6:59pmi attempted to do b and c can you tell me if i did it right?

125...... T1

85.0 ....127 Kelvin 127+ 273= 358

125= 85

T1=358

125*358/85= 526.5

for C i did

V1... -33 C Kelvin -33+273=240

54.0ml....160 C Kelvin 160+273=433

V1=54

240=433

54*240/433=29.9

T1

- chem again -
**DrBob222**, Sunday, April 27, 2008 at 7:26pmc is ok.

b would be ok but you made an error in adding 127 + 273. My calculator gives me 400 and not 358. I THINK you added in 85 which is V2 and not 127 for T2.

**Related Questions**

math - could someone please help. given each set of data for ∆ABC: a) ...

chem - use boyles law to solve for the missing value in the following P1=0.75atm...

Math - 1. Find the value of Sin^-1(-1/2) a. -30 degrees b. 30 degrees c. 150 ...

trig - Use the Law of Sines to solve each triangle. P=110 degrees p=125, r=200 ...

Science-Chemistry - 1. What is Charles’s law? • State the definition of the law ...

Chemistry - How many degrees Centigrade is 125 degrees Fahrenheit? How many ...

math-law of sins - solve the triangle: 1. A= 61 degrees a=8 b=21 2. A=136 ...

chem - Benzaldehyde, C6H5CHO}, has a normal boiling point of 179.0 C and a ...

6th grade math - Which expression could you use to find the measure of an angle ...

Trig - Should the triangle be solved beginning with Law of Sines of Law of ...