Posted by **mike** on Saturday, April 26, 2008 at 1:48pm.

An apartment has a living room whose dimensions are 2.5 m 4.8 m 5.9 m. Assume that the air in the room is composed of 79% nitrogen (N2) and 21% oxygen (O2). At a temperature of 27°C and a pressure of 1.01 105 Pa, what is the mass (in grams) of the air?

- physics -
**DrBob222**, Saturday, April 26, 2008 at 4:21pm
PV = nRT

- physics -
**jessica**, Tuesday, June 24, 2014 at 11:03pm
volume = 2.5 x 4 x 5 = 50

temperature = 22+273.15 = 295.15 k

pressure = 1.01x 10^5 pa

79% of N2 = 0.79

21% of O2 = 0.21

pv = nrt

1.01 x 10^5 x 50 = n x 8.31 x 295.15

n= 2059

n = mass / mass over mole

mass= 2059 x (0.79 x 14*2+0.21 *32)

mass = 5.9*10^4

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**jessica**, Tuesday, June 24, 2014 at 11:04pm
oh just change the temperature and the pressure in my equation. I got the wrong question but overall method is the same. Good luck!

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