Posted by **sam** on Friday, April 25, 2008 at 3:47pm.

if it takes 31,500 joules of heat to warm 750g of water, what was the temperature change?

My answer:

Q = (M) (DeltaT) (c)

Delta T=Q

Delta T = 31,500J

--------

750gx 1.0cal/gCo

Delta T = 42oC