The centers are at (3,5) and at (7,5) along the horizontal line y = 5 and 7-3 = 4 apart
left radius = 5
right radius = 3
the points lie on vertical line x = something an equal distance above and below y = 5
base = 4 along y = 5 line
left leg = 5
right leg = 3
let's use law of cosines to find the angle on the left, between the y = 5 line and the long side length 5
3^2 = 5^2 + 4^2 - 2*5*4 cos A
9 = 25 + 16 - 40 cos A
32 = 40 cos A
A = 36.87 degrees
now the distance from x = 3 to our desired vertical line is
5 cos A which is 5 (32/40) = 4
so our line is
x = 3 + 4 = 7
which we could have said earlier seeing that our triangle is
3, 4, 5 and therefore a right triangle
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