Posted by Pam on Friday, April 25, 2008 at 7:59am.
Please help, my live tutor and I could spent 2 hours trying to solve these two:
find an equation for tangent line y=18^2@ (4,129)
find the derivative of the function:we both kept getting the same answer, but Mathlab kept saying that it was wrong: 4lnl3xl/2+3x
we did the quotient rule, and the chain rule...the derivative and our sign would be wrong...

calculus  Reiny, Friday, April 25, 2008 at 8:21am
I cannot make sense out of your equation, check your typing.

calculus  Reiny, Friday, April 25, 2008 at 12:33pm
for the derivative using the quotient rule I got (8  12x + 12x(ln(3x))) / (x(2+3x)^2)
for the tangent question
dy/dx = 16x
at the point the slope is 16(4) = 64
so using y = mx + b for the tangent equation
129 = 64(4) + b
b = 127
so the tangent equation is y = 64x + 127
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