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March 29, 2015

March 29, 2015

Posted by **Chris Adison** on Thursday, April 24, 2008 at 7:18pm.

MgH = (1/2)*k*(H-2-10)^2 + Mg*2

where did this equation come from. Its not in my book. What concepts does it use?

Is it solved correctly?

MgH = (1/2)*k*(H-2-10)^2 + Mg*2

MgH = 0.5k(H-12)^2 + 2Mg

MgH = 05k(H^2 - 24H + 144) + 2Mg

MgH = 0.5kH^2 - 12kH + 72k + 2Mg

0.5kH^2 - 12kH - MgH + 72k + 2Mg = 0

0.5kH^2 - H(12k + Mg) + (72k + 2Mg) = 0

- physics please help me -
**Quidditch**, Thursday, April 24, 2008 at 8:38pmThe formula looks suspicious. The left side units are MgH and the rightmost term of the right side is Mg*2. Unless H represents some "unitless" parameter (not impossible, but unlikely), the units do not match.

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