Tuesday

September 2, 2014

September 2, 2014

Posted by **Chris Adison** on Thursday, April 24, 2008 at 7:18pm.

MgH = (1/2)*k*(H-2-10)^2 + Mg*2

where did this equation come from. Its not in my book. What concepts does it use?

Is it solved correctly?

MgH = (1/2)*k*(H-2-10)^2 + Mg*2

MgH = 0.5k(H-12)^2 + 2Mg

MgH = 05k(H^2 - 24H + 144) + 2Mg

MgH = 0.5kH^2 - 12kH + 72k + 2Mg

0.5kH^2 - 12kH - MgH + 72k + 2Mg = 0

0.5kH^2 - H(12k + Mg) + (72k + 2Mg) = 0

- physics please help me -
**Quidditch**, Thursday, April 24, 2008 at 8:38pmThe formula looks suspicious. The left side units are MgH and the rightmost term of the right side is Mg*2. Unless H represents some "unitless" parameter (not impossible, but unlikely), the units do not match.

**Answer this Question**

**Related Questions**

physics repost - I am still trying to solve for H in this equation but I am ...

physics repost - I am still trying to solve for H in this equation but I am ...

Physics - How do you use this equation? mgh+1/2mvh=mgh+1/2mv^2+Fd

8th grade math - Your uncle is three years older than your aunt. The product of ...

math - The area of the wall you are going to paint is 50 feet2. If the width is ...

math - someone please help me slove this problem. Use the qudratic formula to ...

Algebra - I am still having trouble solving this problem. Use the quadratic ...

math - I need help solving this equation please. Use the qudratic formula to ...

Math please help! - invested 2000 gains 0.2 every odd numbered month gains 0.15...

physics - how would i go about solving this problem? what formula shoud i use? ...