# Physics

posted by
**Jason** on
.

A powerful particle accelerator, called Large Hadron Collider, will be able to accelerate protons to 14TeV(tetraelectravolt)(1TeV= 10^12eV) of energy.

a)what is the relativistic mass of a proton that has a total energy of 14TeV? (express you answer in MeV/c^2)

to convert 14Tev into MeV I got 1.4x10^7MeV.

Etot = mrel * c^2

mrel= Etot/c^2

=1.4x10^7MeV/9x10^16

=1.55x10^-10 MeV/c^2

b)how many times more massive is such a proton thatn a proton at reset with respect to you, if the proton's rest mass is 1.6726x10^-27 kg = 938.3 MeV/c^2?

Would i simplily divide m_rest/m_rel

so that: 938.3 MeV/c^2 / 1.55x10^-10MeV/c^2

= 6.05x10^12

Isn't this number too large to be a reasonable answer?

c) what is the v/c of such a 14 TeV proton? keep at least 10 digits past the decimal point.

I can't find the (greek symbol of j) so that I can plug it into an equation my teacher gave us. I am really confused with this part of the question.