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Posted by on Wednesday, April 23, 2008 at 1:58pm.

A person wants to participate in a bunjee jump. One end of an elastic band 10m long with a spring constant of 50N/m will be attatched to a basket on a crane and the other end to the waist of the person with a mass of 86kg. The person will step off the edge of the basket to be slowed and brought back by the elastic band before hitting the ground (hopefully 2m above) How high should the crane be? (hint: conservation of energy).

  • physics - , Wednesday, April 23, 2008 at 2:48pm

    Initial PE= Final PE
    mgh=mg2+ 1/2 k(h-12)^2
    check my thinking.

  • physics - , Wednesday, April 23, 2008 at 3:54pm

    could i solve it like this?
    Fg=Fs
    mg=kx
    x=mg/k
    x=stretch-Eq value
    stretch=x+Eq value
    than take the stretch value and add 2.

  • physics - , Wednesday, April 23, 2008 at 4:29pm

    so when i plug the givens into your equation it should look like this

    (86)(9.8)(?)=(86)(9.8)1/2(50)(h-12)^2

    Im confused

  • physics - , Wednesday, April 23, 2008 at 4:13pm

    No, the system is accelerating, Fg does not equal Fs except at equilibrium.

  • physics - , Wednesday, April 23, 2008 at 4:30pm

    so when i plug the givens into your equation it should look like this

    (86)(9.8)(?)=(86)(9.8)1/2(50)(h-12)^2

    im confused

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