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July 5, 2015

Homework Help: calculus

Posted by Pam on Wednesday, April 23, 2008 at 9:03am.

Continuous/discontinuity
Can someone please tell me how to make this determination?

1/x(x-3) x=0,x=-4
is the function con @ x=3
is the function con @ x=0
is the function con @ x=-4

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