Posted by **Pam** on Wednesday, April 23, 2008 at 9:03am.

Continuous/discontinuity

Can someone please tell me how to make this determination?

1/x(x-3) x=0,x=-4

is the function con @ x=3

is the function con @ x=0

is the function con @ x=-4

- calculus -
**bobpursley**, Wednesday, April 23, 2008 at 9:30am
Try to see what the value of the function is on each side of the test point. For instance, on the 3 point, test it at 2.9 and at 3.1 thence closer. Is the function approaching the same point?

Graphing it on your calculator may be easier.

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