Homework Help: Caluculus

Posted by Alice on Tuesday, April 22, 2008 at 8:12pm.

Can anyone help me with this problem?

Suppose that during a controlled experiment, the temperature in a beaker containing some chemical substance at time t is rising at a rate of (15/13)t^2-(7t) degrees centigrade per minute. If the temperature after 1 minute is measured to be 18.6 degrees C, what is the temperature in the test tube after 10 minutes?

Caluculus - bobpursley, Tuesday, April 22, 2008 at 8:14pm
If you integrate the rate, you get temp.

Temp= INT (15/13 t^2 -7t)dt
You know temp at 1 min is 18.6C. Solve for the constant of integration.

Then, you can find the temp after ten min.

Answer this Question

Related Questions

chemistry - 2. Imagine you have two beakers. Both beakers are filled with the ...
Chemistry - Use appropriate chemical principles to explain why water droplets ...
Chemistry - Ok this is my last hope, I totally don't get this question. ...
pre lab Q on chromatography - suppose that there are two components, A and B, in...
physics - During an all-night cram session, a student heats up a 0.420 liter (0....
Chemistry - Suppose u place a beaker containing a solution in the refrigerator. ...
science - we have done experiment in school and for homework we must write ...
science - we have done experiment in school and for homework we must write ...
science - we have done experiment in school and for homework we must write ...
chemistry - A 10.0 g cube of each of the following metals is heated to 100 °...

For Further Reading

First Name:
School Subject:
Answer: