Monday

November 24, 2014

November 24, 2014

Posted by **Connie** on Tuesday, April 22, 2008 at 8:07pm.

(1) x^2+6x-25=0

(2) x^2-6x+25=0

(3) x^2+8x-25=0

(4) x^2-8x+25=0

I have no clue how to do it!!!PLEASE HELP!!!Please guide by step by step!!THANKS A LOT~!!!!

- math-repost -
**bobpursley**, Tuesday, April 22, 2008 at 8:12pmLook at the serds. To get a serd that is negative, you have to have a or c negative. That means only 1 or 3 can be correct. Now, which yields sqrt (b^2-4ac) to be 6i ?

- math-repost -
**Connie**, Tuesday, April 22, 2008 at 11:02pmI still don't get it

**Answer this Question**

**Related Questions**

math - Which equation has the complex number 4-3i as a root? (1) x^2+6x-25=0 (2...

math - Which equation has the complex number 4-3i as a root? 1) x^2+6x-25=0 2) x...

Math - i^6 = (i^2)^3 = (-1)^3 = -1 The square, not the square root of -1 is 1...

College Algebra--Still Confused - I have a few problems I need help with and ...

math - Clue1: I am less than 20. Clue 2: i am an odd number. Clue 3: I am the ...

algebra - Can someone please help me with these problems? Please and thank you. ...

College Algebra - I have a few problems I need help with and also do have ...

Chemistry - 8-hydroxyquinoline (Q) can complex and precipitate many metals. A ...

Complex numbers - quadratic formula - Let a and b be real numbers. The complex ...

Maths - Find the square root of the complex number (a)5+12i Please help