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the density of alumnium is 2.7 g/cm^3 and its molar mass is 27 g/mol. find the mass of an atom of aluminum and the numebr of alumuminum atoms per cubic meter.

  • physics/chem -

    Find the volume of one mole (27/2.7 cm^3). Divide that by avag number, that will be the volume per atom.

  • physics/chem -

    Molar mass is the mass in grams of 1 mole of Al, that is, 1 mol Al has a mass of 27 g.

    On the other hand, 1 mole of any element contains Avogadro's number of atoms, that is,
    1 mol Al = 6.02x10^23 atoms of Al

    Therefore; 6.02x10^23 atoms of Al = 27 g
    1 single Al atom;
    27 g / 6.02x10^23 atoms of Al = 4.48x10^-23 g

    d = 2.7 g / cm^3 means that 1 cm^3 Al has a mass of 2.7 g.
    1 m^3 = 10^6 cm^3 = 2.7x10^6 g
    Mole of Al = 2.7x10^6 g / 27 g/mol = 1x10^5 mol Al

    Since each mole contains 6.02x10^23 atoms of Al
    1x10^5 mol Al will contain;
    1x10^5 mol Al x 6.02x10^23 atoms of Al /mol =
    6.02x10^28 atoms of Al will be per m^3 of Al

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