Posted by **Anonymous** on Tuesday, April 22, 2008 at 9:58am.

Question: A damped harmonic oscillator loses 5.0 percent of its mechanical energy per cycle.

a) By what percentage does its frequency differ from the natural frequency w = sqr(k/m)?

b) After how may periods will the amplitude have decreased to 1/e of its original value?

What equations do I use? I know the final answers are 8.3 * 10^-4 percent and 39 periods. I know that 0.95A is the initial at time T. . .

## Answer This Question

## Related Questions

- damped oscillator - How do I show mathematically that Q is equal to the ...
- Physics - Two different simple harmonic oscillators have the same natural ...
- physic - an object of mass 1.5 kg on a spring of force constant 600N/m loses 3% ...
- Physic Help please - an object of mass 1.5 kg on a spring of force constant 600N...
- Physic Help please - an object of mass 1.5 kg on a spring of force constant 600N...
- Osciallations - A harmonic oscillator has mass 0.530km and an ideal spring with ...
- physics - Which one of these statements regarding standing waves on a string is ...
- PHYSICS - A tube is open only at one end. A certain harmonic produced by the ...
- physics - The velocity of a simple harmonic oscillator is given by; v = + 6.92*...
- Physics - Resonance in a system, such as a string fixed at both ends, occurs ...

More Related Questions